Clipartrequest Clipart
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A media feed of Clipartrequest clipart.en-UShttps://openclipart.org/image/144px/svg_to_png/193993/Openclipart-Scissors-Logo-in-Green.png
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Clipartrequest Clipart144144involute of a circle
https://openclipart.org/detail/203202/involute-of-a-circle
Sat, 11 Oct 2014 21:21:50 -0400Lazur URHx=a*(cos(t)+t*sin(t))
y=a*(sin(t)-t*cos(t))https://openclipart.org/detail/203202/involute-of-a-circlehttp://creativecommons.org/licenses/publicdomain/involute of a circle
https://openclipart.org/detail/203197/involute-of-a-circle
Sat, 11 Oct 2014 20:51:28 -0400Lazur URHProbably the right curve was a circle's involute.
"...Its successive turns are parallel curves with constant separation distance..."
Not sure how this can be proven, but this seems to fit well with the concept of stroked path -as parallel curves at it's edges-.
Mathematical functions for the parametric curve is
x=a*(cos(t)+t*sin(t))
y=a*(sin(t)-t*cos(t))
More info here:
http://en.wikipedia.org/wiki/Involutehttps://openclipart.org/detail/203197/involute-of-a-circlehttp://creativecommons.org/licenses/publicdomain/spectrum of colours 2
https://openclipart.org/detail/202129/spectrum-of-colours-2
Tue, 16 Sep 2014 23:45:39 -0400Lazur URHA test image of linear gradients covering the whole hue range in svg.
Redrawn from scratch, improved version.
This time, only 8 gradients were used in total, so
it renders much smoother.
-after my request, please don't "fix" it-https://openclipart.org/detail/202129/spectrum-of-colours-2http://creativecommons.org/licenses/publicdomain/