Trigonometry Clipart
https://openclipart.org
A media feed of Trigonometry clipart.en-UShttps://openclipart.org/image/144px/svg_to_png/193993/Openclipart-Scissors-Logo-in-Green.png
https://openclipart.org
Trigonometry Clipart144144Sine curve
https://openclipart.org/detail/234920/sine-curve
Thu, 24 Dec 2015 11:11:55 -0400kephalian_cosmosA sine curvehttps://openclipart.org/detail/234920/sine-curvehttp://creativecommons.org/licenses/publicdomain/Scientific Solar Calculator 2
https://openclipart.org/detail/176975/scientific-solar-calculator-2
Fri, 12 Apr 2013 00:25:55 -0400Merlin2525My 2nd remix of a Futuristic Calculator. This time I've added more detail. The formulas are for looks (grin), although I would like this device to be real. Thanks go to the following Open Clip Art Artist: Mathafix for calculatrice.svg, Ilnanny for the battery 1329015443.svg, Bnsonger47 for WirelessIcons.svg
https://openclipart.org/detail/176975/scientific-solar-calculator-2http://creativecommons.org/licenses/publicdomain/Scientific Solar Calculator 1
https://openclipart.org/detail/176974/scientific-solar-calculator-1
Fri, 12 Apr 2013 00:14:48 -0400Merlin2525My remix of a Futuristic Calculator. Thanks go to the following Open Clip Art Artist: Mathafix for calculatrice.svg, Ilnanny for the battery 1329015443.svg, Bnsonger47 for WirelessIcons.svghttps://openclipart.org/detail/176974/scientific-solar-calculator-1http://creativecommons.org/licenses/publicdomain/regular triangle discovery
https://openclipart.org/detail/148285/regular-triangle-discovery
Mon, 04 Jul 2011 21:23:38 -040010binaryI made a discovery about regular triangles today.
For a long time I've wondered, is it possible to create a regular triangle on a computer which
has all of it's points exactly on an integer position. I finally succeeded in doing it with inkscape.
I know almost nothing about the math behind angles. However, when creating lines with the path tool, inkscape displays the angle created by the current location relative to the first point of the line.
For this I used a square grid.
The ratio in pixels I found in the smallest triangle while one corner pointed straight up or down is.
width/height
82/71
How I did this was first use inkscape's polygon tool to automatically create a regular triangle.
Then I made a grid of squares with spacing of 1 pixel. Then I snapped one corner to a grid intersection. Then I tried to follow the triangle and see if it's sides ever crossed an intersection of the grid.
And I was so amazed that it did, and since inkscape lets me automatically snap to the grid, I quickly
made my own triangle path that looks like a really good regular triangle. I'm not sure if I can use this information for pixel art or not but it will be very useful for any vector editor with a square grid.
I'm not sure if this discovery is correct according to geometry,algebra,trigonometry, or whatever other math I know nothing of, but it is at least a good way to approximate a regular triangle on a grid of squares.
https://openclipart.org/detail/148285/regular-triangle-discoveryhttp://creativecommons.org/licenses/publicdomain/shm projection of circular motion
https://openclipart.org/detail/6727/shm-projection-of-circular-motion
Mon, 08 Oct 2007 19:45:00 -0400cbeauFigure shows how the motion of a particle moving at constant angular speed on a circular orbit is projected onto a linear 1D axis. It illustrates how a particle moving on a circular orbit at constant angular speed omega relates to the motion of a horizontal mass-on-a-spring system (the horizontal axis) in simple harmonic motion (SHM).https://openclipart.org/detail/6727/shm-projection-of-circular-motionhttp://creativecommons.org/licenses/publicdomain/shm-state-vs-angle
https://openclipart.org/detail/6726/shmstatevsangle
Mon, 08 Oct 2007 19:36:59 -0400cbeauSimple harmonic motion (SHM) of a particle moving along a circle. The figure shows the sign (direction) of the position, velocity and acceleration of the particle undergoing SHM as a function of the angle.https://openclipart.org/detail/6726/shmstatevsanglehttp://creativecommons.org/licenses/publicdomain/